题外话：如果这个表一共只有2列，id列和name列，很好解决：

 select distinct MIN(id) id,[name] from [t_people] group by [name]

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下面开始正题：

如果这个表除主键id外，还有2至N个列，这N个列里面的数据都一样，则取id最小的那一行数据

如上图，id为：1和3、2和5的数据(除id外)是一样的，则过滤掉id为3和5这两条数据，显示其他数据行

 方法一, 用 group by：

 select MIN(id) id,[name],[age] from [t_people] group by [name],[age] order by id

方法二，用 having：

select * from [t_people] 
where id not in (select max(id)[id] from [t_people] group by [name],[age] having count(*) >1)

方法三，用 临时表 #tmp （不推荐）： 

if OBJECT_ID(N'tempdb..#tmp',N'U') is not null
DROP TABLE  #tmp;
select * into #tmp from [t_people] 
delete from #tmp where id in (select max(id)[id] from #tmp group by [name],[age] having count(*) >1)
select * from #tmp order by id asc
DROP TABLE  #tmp;